4.9t^2=1.3

Solution for 4.9t^2=1.3 equation:

4.9t^2=1.3

We move all terms to the left:

4.9t^2-(1.3)=0

We add all the numbers together, and all the variables

4.9t^2-1.3=0

a = 4.9; b = 0; c = -1.3;
Δ = b2-4ac
Δ = 02-4·4.9·(-1.3)
Δ = 25.48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{25.48}}{2*4.9}=\frac{0-\sqrt{25.48}}{9.8}
=-\frac{\sqrt{}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{25.48}}{2*4.9}=\frac{0+\sqrt{25.48}}{9.8}
=\frac{\sqrt{}}{9.8}
$